(4)/(3)log_(16)(2y^(2)-6y)=1

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Solution for (4)/(3)log_(16)(2y^(2)-6y)=1 equation: 


x in (-oo:+oo)

(4/3)*log_16*(2*y^2-(6*y)) = 1 // - 1

(4/3)*log_16*(2*y^2-(6*y))-1 = 0

(4/3)*log_16*(2*y^2-6*y)-1 = 0

4/3*log_16*(2*y^2-6*y)-1 = 0

4/3*log_16*(2*y^2-6*y)-1 = 0

8/3*log_16*y^2-8*log_16*y-1 = 0

8/3*log_16*y^2-8*log_16*y-1 = 0

x belongs to the empty set

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